Optimal. Leaf size=216 \[ -\frac{b \tan ^2(e+f x) \, _2F_1\left (1,\frac{1}{2} (n p+2);\frac{1}{2} (n p+4);-\tan ^2(e+f x)\right ) \left (c (d \tan (e+f x))^p\right )^n}{f \left (a^2+b^2\right ) (n p+2)}+\frac{a \tan (e+f x) \, _2F_1\left (1,\frac{1}{2} (n p+1);\frac{1}{2} (n p+3);-\tan ^2(e+f x)\right ) \left (c (d \tan (e+f x))^p\right )^n}{f \left (a^2+b^2\right ) (n p+1)}+\frac{b^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n \, _2F_1\left (1,n p+1;n p+2;-\frac{b \tan (e+f x)}{a}\right )}{a f \left (a^2+b^2\right ) (n p+1)} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.390999, antiderivative size = 216, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {6677, 961, 64, 808, 364} \[ -\frac{b \tan ^2(e+f x) \, _2F_1\left (1,\frac{1}{2} (n p+2);\frac{1}{2} (n p+4);-\tan ^2(e+f x)\right ) \left (c (d \tan (e+f x))^p\right )^n}{f \left (a^2+b^2\right ) (n p+2)}+\frac{a \tan (e+f x) \, _2F_1\left (1,\frac{1}{2} (n p+1);\frac{1}{2} (n p+3);-\tan ^2(e+f x)\right ) \left (c (d \tan (e+f x))^p\right )^n}{f \left (a^2+b^2\right ) (n p+1)}+\frac{b^2 \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n \, _2F_1\left (1,n p+1;n p+2;-\frac{b \tan (e+f x)}{a}\right )}{a f \left (a^2+b^2\right ) (n p+1)} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 6677
Rule 961
Rule 64
Rule 808
Rule 364
Rubi steps
\begin{align*} \int \frac{\left (c (d \tan (e+f x))^p\right )^n}{a+b \tan (e+f x)} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (c (d x)^p\right )^n}{(a+b x) \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{\left ((d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{(d x)^{n p}}{(a+b x) \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{\left ((d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \left (\frac{b^2 (d x)^{n p}}{\left (a^2+b^2\right ) (a+b x)}+\frac{(d x)^{n p} (a-b x)}{\left (a^2+b^2\right ) \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{\left ((d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{(d x)^{n p} (a-b x)}{1+x^2} \, dx,x,\tan (e+f x)\right )}{\left (a^2+b^2\right ) f}+\frac{\left (b^2 (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{(d x)^{n p}}{a+b x} \, dx,x,\tan (e+f x)\right )}{\left (a^2+b^2\right ) f}\\ &=\frac{b^2 \, _2F_1\left (1,1+n p;2+n p;-\frac{b \tan (e+f x)}{a}\right ) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{a \left (a^2+b^2\right ) f (1+n p)}+\frac{\left (a (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{(d x)^{n p}}{1+x^2} \, dx,x,\tan (e+f x)\right )}{\left (a^2+b^2\right ) f}-\frac{\left (b (d \tan (e+f x))^{-n p} \left (c (d \tan (e+f x))^p\right )^n\right ) \operatorname{Subst}\left (\int \frac{(d x)^{1+n p}}{1+x^2} \, dx,x,\tan (e+f x)\right )}{\left (a^2+b^2\right ) d f}\\ &=\frac{a \, _2F_1\left (1,\frac{1}{2} (1+n p);\frac{1}{2} (3+n p);-\tan ^2(e+f x)\right ) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{\left (a^2+b^2\right ) f (1+n p)}+\frac{b^2 \, _2F_1\left (1,1+n p;2+n p;-\frac{b \tan (e+f x)}{a}\right ) \tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n}{a \left (a^2+b^2\right ) f (1+n p)}-\frac{b \, _2F_1\left (1,\frac{1}{2} (2+n p);\frac{1}{2} (4+n p);-\tan ^2(e+f x)\right ) \tan ^2(e+f x) \left (c (d \tan (e+f x))^p\right )^n}{\left (a^2+b^2\right ) f (2+n p)}\\ \end{align*}
Mathematica [A] time = 0.694239, size = 166, normalized size = 0.77 \[ \frac{\tan (e+f x) \left (c (d \tan (e+f x))^p\right )^n \left (a^2 (n p+2) \, _2F_1\left (1,\frac{1}{2} (n p+1);\frac{1}{2} (n p+3);-\tan ^2(e+f x)\right )+b \left (b (n p+2) \, _2F_1\left (1,n p+1;n p+2;-\frac{b \tan (e+f x)}{a}\right )-a (n p+1) \tan (e+f x) \, _2F_1\left (1,\frac{n p}{2}+1;\frac{n p}{2}+2;-\tan ^2(e+f x)\right )\right )\right )}{a f \left (a^2+b^2\right ) (n p+1) (n p+2)} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.59, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( c \left ( d\tan \left ( fx+e \right ) \right ) ^{p} \right ) ^{n}}{a+b\tan \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n}}{b \tan \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n}}{b \tan \left (f x + e\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \left (d \tan{\left (e + f x \right )}\right )^{p}\right )^{n}}{a + b \tan{\left (e + f x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (\left (d \tan \left (f x + e\right )\right )^{p} c\right )^{n}}{b \tan \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]